-16x^2+5x+40=29

Solution for -16x^2+5x+40=29 equation:

-16x^2+5x+40=29

We move all terms to the left:

-16x^2+5x+40-(29)=0

We add all the numbers together, and all the variables

-16x^2+5x+11=0

a = -16; b = 5; c = +11;
Δ = b2-4ac
Δ = 52-4·(-16)·11
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-27}{2*-16}=\frac{-32}{-32}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+27}{2*-16}=\frac{22}{-32}
=-11/16
$